Áp dụng BĐT AM-GM:
\(P\ge12\sqrt[12]{\dfrac{a^3.b^4.c^5}{a^9.b^8.c^7}}=12\sqrt[12]{\dfrac{1}{a^6.b^4.c^2}}=12\sqrt[12]{\dfrac{1}{a^2.a^2.a^2.b^2.b^2.c^2}}\)
\(\ge12\sqrt[12]{\dfrac{1}{\dfrac{\left(3a^2+2b^2+c^2\right)^6}{6^6}}}\ge12\sqrt{6}\)
Dấu = xảy ra khi \(a=b=c=\dfrac{1}{\sqrt{6}}\)