\(\dfrac{x+2}{3x}+\dfrac{x-5}{5x}+\dfrac{x+8}{4x}\) MTC: \(60x\)
\(=\dfrac{20\left(x+2\right)}{60x}+\dfrac{12\left(x-5\right)}{60x}+\dfrac{15\left(x+8\right)}{60x}\)
\(=\dfrac{20\left(x+2\right)+12\left(x-5\right)+15\left(x+8\right)}{60x}\)
\(=\dfrac{20x+40+12x-60+15x+120}{60x}\)
\(=\dfrac{47x+100}{60x}\)