Question

BT:

1Tim x

a)(x+2)(x+3)-(x-2)(x+5)=6

b)3(1-4x)(x-1)+4(3x-2)(x+3)=-27

c)5(2x+3)(y+2)-2(5y-4)(y-1)=75

d)(3x+2)(2x+9)-(x+2)(6x+1)=(x+1)-(x-6)

Answer 1

a: \(\Leftrightarrow x^2+5x+6-\left(x^2+3x-10\right)=6\)

\(\Leftrightarrow x^2+5x+6-x^2-3x+10=6\)

=>2x+16=6

=>2x=-10

hay x=-5

b: \(\Leftrightarrow3\left(x-1-4x^2+4x\right)+4\left(3x^2+9x-2x-6\right)=-27\)

\(\Leftrightarrow3\left(-4x^2+5x-1\right)+4\left(3x^2+7x-6\right)=-27\)

\(\Leftrightarrow-12x^2+15x-3+12x^2+28x-24=-27\)

=>43x=0

hay x=0

c: \(\Leftrightarrow5\left(2y^2+4y+3y+6\right)-2\left(5y^2-5y-4y+4\right)=75\)

\(\Leftrightarrow10y^2+35y+30-10y^2+18y-8=75\)

=>53y=53

hay y=1

d: \(\Leftrightarrow6x^2+27x+4x+18-\left(6x^2+x+12x+2\right)=x+1-x+6=7\)

\(\Leftrightarrow6x^2+31x+18-6x^2-13x-2=7\)

=>18x+16=7

=>18x=-9

hay x=-1/2