Bài 2:
a: \(\Leftrightarrow3x^2+10x-8=0\)
\(\Leftrightarrow3x^2+12x-2x-8=0\)
=>(x+4)(3x-2)=0
=>x=2/3 hoặc x=-4
b: \(\Leftrightarrow x^4+2x^3-4x-4=0\)
\(\Leftrightarrow\left(x^2-2\right)\left(x^2+2\right)+2x\left(x^2-2\right)=0\)
\(\Leftrightarrow x^2-2=0\)
hay \(x=\pm\sqrt{2}\)