Question

Bài 1: Khai triển các đẳng thức sau:

a) (x+3)²

b) (4x² - 9)²

c) (x + \(\dfrac{1}{2}\))²

d) (x - \(\dfrac{3}{2}\))²

e) x² - 4

f) x² - 289

Answer 1

\(x+3^2=x^2+2.x.3+3^2=x^2+6x+9\)

\(4x^{^{ }2}-9=4x^2-2.4x.9+9^2=16x^2-72x+81\)

\(\left(x-\dfrac{3}{2}\right)^2=x^2-2.x.\dfrac{3}{2}+\dfrac{3}{2}^2=x^2-3x+\dfrac{9}{4}\)

Answer 2

\(\left(x+3\right)^2=x^2+6x+9\)

\(\left(4x^2-9\right)^2=16x^4-72x^2+81\)

\(\left(x+\dfrac{1}{2}\right)^2=x^2+x+\dfrac{1}{4}\)

\(\left(x-\dfrac{3}{2}\right)^2=x^2-3x+\dfrac{9}{4}\)

\(x^2-4=\left(x+2\right)\left(x-2\right)\)

\(x^2-289=\left(x+17\right)\left(x-17\right)\)

Answer 3

- Vỳ ko còn tg nên mềnh giúp bn đc đến đây thoyy <'

Soriii