Question

a.2x^3 (2x-3) -x^2 (4x^2 -6x+2)=0

b.(x+3)^2 + (x-2) ( x+2) - 2(x-1)^2=7

c.(3x +2)(x-1) -3(x+1) (x-2) =4

giúp mình nha

Answer 1

\(a,2x^3\left(2x-3\right)-x^2\left(4x^2-6x+2\right)=0\)

\(\Rightarrow4x^4-6x^3-4x^4+6x^3-2x^2=0\)

\(\Rightarrow-2x^2=0\)

\(\Rightarrow x^2=0\)

\(\Rightarrow x=0\)

\(b,\left(x+3\right)^2+\left(x-2\right)\left(x+2\right)-2\left(x-1\right)^2=7\)

\(\Rightarrow x^2+6x+9+x^2-4-2x^2+4x-2=7\)

\(\Rightarrow10x+3=7\)

\(\Rightarrow10x=4\)

\(\Rightarrow x=\dfrac{2}{5}\)

\(c,\left(3x+2\right)\left(x-1\right)-3\left(x+1\right)\left(x-2\right)=4\)

\(\Rightarrow3x^2-x-2-3x^2+3x+6=4\)

\(\Rightarrow2x+4=4\)

\(\Rightarrow2x=0\)

\(\Rightarrow x=0\)

Answer 2

đó là tìm x nhé mn