Ta có:
\(\left(2^2\right)^{2x-1}=\left(\frac{1}{2}\right)^3\)
\(2^{2\left(2x-1\right)}=2^{-3}\)
\(\Rightarrow2\left(2x-1\right)=-3\)
\(2x-1=-3:2=-\frac{3}{2}\)
\(2x=-\frac{3}{2}+1=-\frac{1}{2}\)
\(x=-\frac{1}{2}:2=-\frac{1}{4}\)
42x-1 = 1/8
8.42x-1 = 1
23.(22)2x-1 = 1
23.24x-2 = 1
24x-2+3 = 1
24x+1 = 20
4x + 1 = 0
4x = -1
x = -1 : 4
x = -0,25