Ta có:
\(\left(2^2\right)^{2x-1}=\left(\frac{1}{2}\right)^3\)
\(2^{2\left(2x-1\right)}=2^{-3}\)
\(\Rightarrow2\left(2x-1\right)=-3\)
\(2x-1=-3:2=-\frac{3}{2}\)
\(2x=-\frac{3}{2}+1=-\frac{1}{2}\)
\(x=-\frac{1}{2}:2=-\frac{1}{4}\)
42x-1 = 1/8
8.42x-1 = 1
23.(22)2x-1 = 1
23.24x-2 = 1
24x-2+3 = 1
24x+1 = 20
4x + 1 = 0
4x = -1
x = -1 : 4
x = -0,25
tính
1, 125^5:25^7
2, 27^8:9^9
3,36^5:6^8
4, 49^6:7^10
5, 7^20:49^9
6, 1/2^10:1/8^3
7, (-1/2)^21:1/4^10
8,1/16^5:(-1/2)^18
9,1/5^30:1/25^14
10, 1/125^6:1/25^14
A=1/2^2 +1/2^4 +1/2^6 +1/2^8 +⋯+1/2^100 CM: A<1/3
(2x-1)mũ 6 =(2x-1)mũ 8
(x-3)^2=1
(2x+1)^3=-8
(x-1/4)^2=1/25
Giúp mình với mai nộp òi
(X-1/3)3=8/27
(5/3)6×x=(1/2)8×(10/3)8
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giúp mình với ạ
a) 2x-1.3y+1=12x+y b) 3x = 9y-1 và 8y = 2x+8
Tìm x, y biết:
a) \(3^x=9^{y-1}\) với \(8^y=2^{x+8}\)
b) \(\left(2x-1\right)^2+\left(4y-1\right)^4=0\)
Tính:
(/x/-\(\dfrac{1}{8}\)).(\(\dfrac{-1}{5}\))5=(-\(\dfrac{1}{8}\))7
Làm ơn giúp mn nha!!! ✔
tìm n
\(\left(\dfrac{1}{2}\right)^{2n-1}=\left(\dfrac{1}{8}\right)\)
