Question

(3x+1)^2-9x(x-1)=16

tìm x

Answer 1

`(3x + 1)^2 - 9x.(x-1)=16`

`9x^2 + 6x + 1 - 9x^2 - 9x = 16`

`(9x^2 - 9x^2) + (6x +9x) + 1 = 16`

` 0 + 15x + 1 = 16`

`15x+1=16`

`15x = 16-1`

`15x = 15`

`x =1`

Answer 2

\(\Leftrightarrow9x^2+6x+1-9x^2+9x=16\)

=>15x+1=16

hay x=1