ĐKXĐ: ...
\(\Leftrightarrow12x^2-3x-1-4x\sqrt{3x+1}=0\)
\(\Leftrightarrow16x^2-\left(4x^2+4x\sqrt{3x+1}+3x+1\right)=0\)
\(\Leftrightarrow16x^2-\left(2x+\sqrt{3x+1}\right)^2=0\)
ĐKXĐ: ...
\(\Leftrightarrow12x^2-3x-1-4x\sqrt{3x+1}=0\)
\(\Leftrightarrow16x^2-\left(4x^2+4x\sqrt{3x+1}+3x+1\right)=0\)
\(\Leftrightarrow16x^2-\left(2x+\sqrt{3x+1}\right)^2=0\)
Giải PT : \(3x-1+\frac{x-1}{4x}=\sqrt{3x+1}\)
a)\(\sqrt{1-x}\left(x-3x^2\right)=x^3-3x^2+2x+6\)
b)\(x^2+x+12\sqrt{x+1}=36\)
c)\(3x-1+\frac{x-1}{4x}=\sqrt{3x+1}\)
d)\(\sqrt{x^2+12}-3x=\sqrt{x^2+5}-5\)
e)\(4x^2+12+\sqrt{x-1}=4\left(x\sqrt{5x-1}+\sqrt{9-5x}\right)\)
f)\(4x^3-25x^2+43x+x\sqrt{3x-2}=22+\sqrt{3x-2}\)
g)\(2\left(x+1\right)\sqrt{x}+\sqrt{3\left(2x^3+5x^2+4x+1\right)}=5x^3-3x^2+8\)
h)\(\sqrt{x^2+12}-\sqrt{x^2+5}=3x-5\)
i)\(\sqrt{1-3x}-\sqrt[3]{3x-1}=\left|6x-2\right|\)
k)\(\sqrt{2x^3+3x^2-1}=2x^2+2x-x^3-1\)
l)\(\sqrt{x^2+x-2}+x^2=\sqrt{2\left(x-1\right)}+1\)
Tìm ĐKXĐ của các căn thức sau
a, \(\sqrt{5-4x}\)
b, \(\sqrt{\frac{-5}{3x-4}}\)
c, \(\sqrt{x^2+7}\)
d, \(\sqrt{x^2-4x+4}\)
n, \(\sqrt{\frac{3x-5}{x+1}}\)
m, \(\sqrt{\frac{x^2}{3x-1}}\)
g, \(\frac{\sqrt{x-1}}{\sqrt{5-2x}}\)
Giải phương trình vô tỉ:
a) \(1+\frac{2}{3}\sqrt{x-x^2}=\sqrt{x}+\sqrt{1-x}\)
b) \(\sqrt{2x+3}+\sqrt{x+1}=3x+2\sqrt{2x^2+5x+3}-2\)
c) \(\sqrt{7x+7}+\sqrt{7x-6}+2\sqrt{49x^2+7x-42}=181-4x\)
d) \(\frac{\sqrt{x+4}+\sqrt{x-4}}{2}=x+\sqrt{x^2-16}-6\)
e) \(5\sqrt{x}+\frac{5}{2\sqrt{x}}=2x+\frac{1}{2x}+4\)
g) \(\sqrt{3x-2}+\sqrt{x-1}=4x-9+2\sqrt{3x^2-5x+2}\)
giải pt
\(\sqrt{3x+1}-\sqrt{2-x}=\frac{4x-1}{3}\)
Giải phương trình vô tỉ:
a) \(4x^2-4x-10=\sqrt{8x^2-6x-10}\)
b) \(\sqrt{\left(x+1\right)\left(2-x\right)}=1+2x-2x^2\)
c) \(\sqrt{3x+8+6\sqrt{3x-1}}+\sqrt{3x+8-6\sqrt{3x-1}}=3x+4\)
d) \(2x\sqrt{x^2-x+1}+4\sqrt{3x+1}=2x^2+2x+6\)
a) Giai PT : 3x - 1 +\(\frac{x-1}{4x}=\sqrt{3x+1}\)
b) Giai hệ PT sau :
\(\left\{{}\begin{matrix}x^3-y^3=4x+2y\\x^2-1=3\left(1-y^2\right)\end{matrix}\right.\)
Giải phương trình bằng cách đặt ẩn phụ
1, \(\left(4x+2\right)\sqrt{x+8}=3x^2+7x+8\)
2, \(x^2+4x+1-2x\sqrt{3x+1}=\sqrt{3x+1}\)
3, \(3x^2+2x+3=\left(3x+1\right)\sqrt{x^2+3}\)
Giải phương trình:
\(3x-1+\dfrac{x-1}{4x}=\sqrt{3x+1}\)