\(\left(2x-3\right)^3=8x^3-36x^2+54x-27\)
\(4x^2-16=\left(2x-4\right)\left(2x+4\right)=4\left(x-2\right)\left(x+2\right)\)
a) \(\left(2x-3\right)^3\)
\(=\left(2x\right)^3-3\cdot\left(2x\right)^2\cdot3+3\cdot2x\cdot3^2-3^3\)
\(=8x^3-3\cdot4x^2\cdot3+3\cdot2x\cdot9-27\)
\(=8x^3-36x^2+54x-27\)
b) \(4x^2-16\)
\(=4\left(x^2-4\right)\)
\(=4\left(x-2\right)\left(x+2\right)\)
(2x-3)3 = 8x3 - 36x2 + 54x +- 273
4x2-16 = (2x-4).(2x+4)