\(\left(2x-3\right)^2-\left(2x+3\right)\left(2x+3\right)=\left(2x-3\right)^2-\left(2x+3\right)^2\)
Áp dụng HĐT \(a^2-b^2=\left(a+b\right)\left(a-b\right)\) rồi rút gọn tiếp nha bn
(2x+3)^2+(2x+3)^2-2(2x-3)(2x-3)
Rút gọn :
1. (2x-5)(3x+1)-(x-3)^2+(2x+5)^2-(3x+1)^3
2. (2x-1)(2x+1)-3x-2)(2x+3)-(x-1)^3+(2x+3)^3
3. (x-2)(x^2+2x+4)-(3x-2)^3+(3x-4)^2
4. (7x-1)(8x+2)-(2x-7)^2-(x-4)^3-(3x+1)^3
5. (5x-1)(5x+1)-(x+3)(x^2-3x+9)-(2x+4)^2-(3x-4)^2+(2x-5)^3
6. (4x-1)(x+2)-(2x+5)^2-(3x-7)^2+(2x+3)^3=(3x-1)^3
Bài 1: Khai triển hằng đẳng thức:
a, ( x - y + 2z )2
b, ( 2x-3 ). ( 2x+3 ) . ( 4x2+9 )
Bài 2: Rút gọn biểu thức:
a, ( 5x+2 ).( 2-5x ) - ( 3x+2 ).( 2x+5 )2
b, ( -2x-3 )2 + 2(2x+1).( 2x+5 ) + ( 2x+5 )2
1.(x+2)3+(x-3)2-x2(x+5)
2.(2x+3).(x-5)+2x(3-x)+x-10
3.(-x-2)3+(2x-4).(x2+2x+4)-x2.(x-6)
(2x-1)^2-(x-3)(2x+5)
x(2x-5)-3(3x-1)^2.x-3x
(3x-1)^3-(2x-1)(4x^2+4x+1)
(1+3x)(1-3x+9x^2)-(2x-1)^3
2(x-3)(x+3)-x(2x-1)(x-3)
ai giúp mình với khó quá:<
Rút gọn: (2x+3)2 +(2x+5)2 - 2(2x+3) (2x+5)
tìm x biết ;
(x-3)^3 - (2x+1).(4x^2+1^2) = (x+2)^3-(2x-3)^3-18x (2x-3)
1.(x+2)3+(x-3)2-x2(x+5)
2.(2x+3).(x-5)+2x(3-x)+x-10
3.(x+5).(x2-5x+25)-x(x-4)2+16x
4.(-x-2)3+(2x-4).(x2+2x+4)-x2.(x-6)
phân tích các đa thức sau thành nhân tử:
a) (ab-1)^2 + (a+b)^2
b) x^3+2x^2+2x+1
c) x^3-4x^2+12x-27
d)x^4-2x^3+2x-1
e)x^4+2x^3+2x^2+2x+1
