\(2\left(5x-8\right)-3\left(4x-5\right)=4\left(3x-4\right)+11\)
\(\Leftrightarrow10x-16-12x+15=12x-16+11\)
\(\Leftrightarrow-2x-1=12x-5\)
\(\Leftrightarrow4=14x\Leftrightarrow x=\dfrac{2}{7}\)
Vậy...
\(2\left(5x-8\right)-3\left(4x-5\right)=4\left(3x-4\right)+11\)
\(\Leftrightarrow10x-16-12x+15=12x-16+11\)
\(\Leftrightarrow10x-16-12x+15-12x+16-11=0\)
\(\Leftrightarrow-14x+4=0\Leftrightarrow14x=4\Leftrightarrow x=\dfrac{4}{14}=\dfrac{2}{7}\) vậy \(x=\dfrac{2}{7}\)