\(2-\left|x-\dfrac{2}{5}\right|=\dfrac{-1}{2}\\ \left|x-\dfrac{2}{5}\right|=2-\left(\dfrac{-1}{2}\right)\\ \left|x-\dfrac{2}{5}\right|=\dfrac{5}{2}\\ TH1:x-\dfrac{2}{5}=\dfrac{5}{2}\\ x=\dfrac{5}{2}+\dfrac{2}{5}\\ x=\dfrac{29}{10}\\ TH2:x-\dfrac{2}{5}=\dfrac{-5}{2}\\ x=\dfrac{-5}{2}+\dfrac{2}{5}\\ x=\dfrac{-21}{10}\)
<=> 2-x+2/5=-1/2
<=> x=2+2/5+1/2
<=> x= 29/10