a) (X - 2)\(^2\) = 1 <=> X - 2 = \(\sqrt{1}\) <=> X = 1 + 2 <=> X = 3
a) (X - 2)\(^2\) = 1 <=> X - 2 = \(\sqrt{1}\) <=> X = 1 + 2 <=> X = 3
1)tìm x biết:
a)(x-2)^2=1
b)(2x-1)^3=-8
c)(x+1/2)^2=1/16
d)(x-2)^3=-27
e(2x-3)^2=25
g)3^x-1=1/243
h)2^x+2^x+3=144
k)81^-2x*27^x=95
Tìm x
a) x-6/7 + x-7/8 + x-8/9 = x-9/10 + x-10/11+x-11/12
b) x+32/11 + x+23/12 = x+38/13 + x+27/14
c) | x-2| = 13
d) 3|x-2| + |4x-8| = |-2| - |1/3|
e) |3x-2|+5^-1 = 3 + | x- (2/3) |
f) | x+2 | + | x-2 | = 3
g) (2x-1)^2 - 5 = 20
i) (x+2)^2 = 1/2 - 1/3
k) (x-1)^3 = (x-1)
m) (x-1)^x+2 = (x-1)^2
n) (x+3)^y+1 = (2x-1)^y+1 vs y là 1 số tự nhiên .
Tìm x:
a)\(-4.\left[2.\left(x-4\right)-3.\left(5x-1\right)\right]+2x-8=12\)
b)3x.2x=216
c)27<813:3x<243
d)(x-7)x+1-(x-7)x+11=0
Tìm nghiệm của các đa thức sau:
\(A=-\dfrac{2}{3}x-\dfrac{5}{9}\) \(B=x^2-\dfrac{4}{25}\) \(C=\dfrac{1}{2}x^3+\dfrac{4}{27}\) \(D=x^3-\dfrac{1}{8}x\)
\(E=-\dfrac{16}{81}+x^4\) \(F=-x.\left(-2x+3\right).\left(1-x^3\right)\) \(I=2.\left(2-x\right)+\dfrac{1}{2}\left(x-2\right)^2\) \(G=x^{100}-8.x^{97}\)
1. Tìm x:
a. |x| = 5,6 b. |x-3,5| = 5 c.|x+\(\dfrac{3}{4}\)| - \(\dfrac{1}{2}\)= 0 d. |4x| -|-13,5| = |\(\dfrac{9}{4}\)|
e. (x-1)3 = 27 f. (2x-3)2=36 g. 5x + 2= 625 h. (2x -1) 3 = -8
i.* \(\dfrac{1}{4}\).\(\dfrac{2}{6}.\dfrac{3}{8}.\dfrac{4}{10}.\dfrac{5}{12}...\dfrac{30}{62}.\dfrac{31}{64}=2^x\)
1. Viết số 25 dưới dạng lũy thừa. Tìm tất cả cánh viết.
2. Tìm x thuộc Q, biết rằng:
a, ( x - 1/2 )^2 = 0;
b, ( x - 2 )^2 = 1;
c, ( 2x - 1 )^3 = -8;
d, ( x + 1/2 )^2 = 1/16.
bài 1 : tính
a) (5-xy)2
b) (3-2y)2
c) (3+x2) . (3-x2)
d) (5x-2y).( 25x2+10xy+4y2)
e) (3x+y). (9x2-3xy+y2)
g) (2x-1)3
bài 2 : viết các biểu thức sau về dạng tích
a) x2-2x+1
b) 4x2+12x+9
c) x3-27
d) 8x3+1
e) 4x2-1
g) x3-9x2+27x-27
h) x3+6x2+12x+8
bài 3 : rút gọn
a) ( x+3)2-(x-1)2
b) (3x+2).(3x-2)-9.(x+2).(x-2)
c) (x-3).(x2+3x+9)-(x3-5)
d) (x+1)3-x2(x+2)
e) (4x+y).(16x2-4xy+y2)-(4x-y).(16x2+4xy+y2)
Tìm x: a) 8< 2^x < 2^9 * 2^-5
b) 27 < 81^3 / 3^x < 243
c) (2/5)^x > (5\2)^-3*(-2\5)^2
d) (-3/4)^3x-1 = 256/81Tìm x: a) 8< 2^x < 2^9 * 2^-5
b) 27 < 81^3 / 3^x < 243
c) (2/5)^x > (5\2)^-3*(-2\5)^2
d) (-3/4)^3x-1 = 256/81