Câu 2:
\(\dfrac{x-10}{30}+\dfrac{x-14}{43}+\dfrac{x-5}{95}+\dfrac{x-148}{8}=0\)
\(\Leftrightarrow\left(\dfrac{x-10}{30}-3\right)+\left(\dfrac{x-14}{43}-2\right)+\left(\dfrac{x-5}{95}-1\right)+\left(\dfrac{x-148}{8}+6\right)=0\)
=>x-100=0
hay x=100
a) Tìm x thỏa mãn: \(\dfrac{x-10}{30}+\dfrac{x-14}{43}+\dfrac{x-5}{95}+\dfrac{x-148}{5}=0\)
b) Tìm số nguyên x,y biết: 42 - 3|y - 3| = 4(2012 - x)4
Tìm x :
a)\(\dfrac{x-1}{50}+\dfrac{x-2}{49}=\dfrac{x-3}{48}+\dfrac{x-4}{47}\)
b)\(\dfrac{x+25}{6}+\dfrac{x+20}{11}+\dfrac{x+16}{15}+3=0\)
c)\(\dfrac{x-15}{6}+\dfrac{x-10}{11}=\dfrac{x-3}{18}+\dfrac{x-7}{14}\)
Tìm x:
3\(\dfrac{1}{14}\) - 5\(\dfrac{1}{3}\) - \(\dfrac{4}{7}\) + \(\dfrac{11}{21}\) = x -\(\dfrac{1}{2}\)
Làm ra bài giải giúp mk vs
tìm x biết
a) \(\dfrac{1}{2}x+2\dfrac{1}{2}=3\dfrac{1}{2}x-\dfrac{3}{4}\)
b) \(\dfrac{2}{3}x-\dfrac{2}{5}=\dfrac{1}{2}x-\dfrac{1}{3}\)
c) \(\dfrac{1}{3}x+\dfrac{2}{5}\left(x+1\right)=0\)
d) \(\dfrac{2}{3}-\dfrac{1}{3}\left(x-\dfrac{3}{2}\right)-\dfrac{1}{2}\left(2x+1\right)=5\)
e) \(\dfrac{x+2015}{5}+\dfrac{x+2016}{4}=\dfrac{x+2017}{3}+\dfrac{x+2018}{2}\)
tìm x;y
b \(\left|x-y\right|+\left|y+\dfrac{9}{25}=0\right|\)
c \(\left(\dfrac{1}{2}x-5\right)^{20}+\left(y^2-\dfrac{1}{4}\right)^{10}=0\)
a \(\left|\dfrac{1}{2}-\dfrac{1}{3}+x\right|=\dfrac{-1}{4}-y\)
d \(\left|x\left(x^2-\dfrac{5}{4}\right)\right|=x\) \(\left(x\ge0\right)\)
e \(x^2+\left(y-\dfrac{1}{10}\right)^4=0\)
1. Tìm x, biết :
a) 27x : 3x = 9
b) 25 : 5x = 5
c) 2 : (x + 2)2 = \(\dfrac{1}{18}\)
d) (5x - 1)2 = \(\dfrac{36}{49}\)
e) \(\left(\dfrac{3}{4}\right)^x=\dfrac{2^8}{3^4}\)
g) \(\left(\dfrac{-2}{5}\right)^x=\dfrac{16}{625}\)
h) 5(x-2)(x+3)=(-17)0
i) (x - 2)8=(x - 2)6
k) (x + 1)7=(x + 1)5
l) (3x - 1)2n+1=82n+1
1, Tìm x, biết
a, (2x+3).(3x-5) \(\ge\) 0
b, \(\dfrac{x}{3-x}\) > -1
c, \(\dfrac{3}{2}\) \(\le\) \(\dfrac{x-1}{x+5}\)
d, \(\dfrac{7}{4x^2-1}\) \(\ge\) 0
e, \(\dfrac{7}{x^2-3}\) > 1
Tìm x biết :
1) \(\dfrac{-7}{x+1}=\dfrac{-x-1}{\dfrac{4}{7}}\)
2) \(\dfrac{x-3}{x+5}=\dfrac{5}{7}\)
3) \(\dfrac{x+1}{2x+1}=\dfrac{0,5x+2}{x+3}\)
4) \(\dfrac{3x+2}{5x+7}=\dfrac{3x-1}{5x+1}\)
Tìm x
a) \(\left(\dfrac{3}{5}x-\dfrac{2}{3}x-x\right)\cdot\dfrac{1}{7}=-\dfrac{5}{21}8\)
b) \(\left(5x-1\right)\cdot\left(2x+\dfrac{1}{3}\right)=0\)
c) \(\dfrac{5\left|x+1\right|}{2}=\dfrac{90}{\left|x+1\right|}\)
