Question

1.phân tích đa thức sau thành nhân tử.

a, x⁴+x²+1

b,x²(x-1) - 4x²+8x-4=0

c,x¹⁰+x³²+1

d,x⁶⁴+x³²+1

e,x⁴-3x²+9

Answer 1

\(x^4+x^2+1=x^4+2x^2+1-x^2=\left(x^2+1\right)^2-x^2=\left(x^2-x+1\right)\left(x^2+x+1\right)\)

\(x^2\left(x-1\right)-4\left(x-1\right)^2=\left(x-1\right)\left(x^2-4\left(x-1\right)\right)=\left(x-1\right)\left(x-2\right)^2\)

c/ Coi lại đề

d/ \(x^{64}+2x^{32}+1-x^{32}=\left(x^{32}+1\right)^2-\left(x^{16}\right)^2=\left(x^{32}-x^{16}+1\right)\left(x^{32}+x^{16}+1\right)\)

e/ \(x^4+6x^2+9-9x^2=\left(x^2+3\right)^2-\left(3x\right)^2=\left(x^2-3x+3\right)\left(x^2+3x+3\right)\)