a: ĐKXĐ: a>0;a<>9
b: \(B=\dfrac{3\sqrt{a}-a+a+9}{9-a}:\dfrac{3\sqrt{a}+1-\sqrt{a}+3}{\sqrt{a}\left(\sqrt{a}-3\right)}\)
\(=\dfrac{3\left(\sqrt{a}+3\right)}{-\left(\sqrt{a}-3\right)\left(\sqrt{a}+3\right)}\cdot\dfrac{\sqrt{a}\left(\sqrt{a}-3\right)}{2\sqrt{a}+4}\)
\(=\dfrac{-3\sqrt{a}}{2\sqrt{a}+4}\)
c: Để B<-1 thì B+1<0
=>-3 căn a+2căn a+4<0
=>-căn a<-4
=>a>16