\(m,\dfrac{2}{x-3}+\dfrac{3}{x+3}=\dfrac{3x+5}{x^2-9}\left(x\ne\pm3\right)\\ \Leftrightarrow\dfrac{2}{x-3}+\dfrac{3}{x+3}-\dfrac{3x+5}{\left(x-3\right)\left(x+3\right)}=0\\ \Leftrightarrow\dfrac{2\left(x+3\right)}{\left(x-3\right)\left(x+3\right)}+\dfrac{3\left(x-3\right)}{\left(x+3\right)\left(x-3\right)}-\dfrac{3x+5}{\left(x-3\right)\left(x+3\right)}=0\\ \Rightarrow2x+6+3x-9-3x-5=0\\ \Leftrightarrow2x-8=0\\ \Leftrightarrow2x=8\\ \Leftrightarrow x=4\)
\(n,\dfrac{3x-1}{x^2-9}=\dfrac{2}{x-3}-\dfrac{1}{x+3}\\\left(\text{đ}k\text{x}\text{đ}:x\ne\pm3\right)\\ \Leftrightarrow\dfrac{3x-1}{\left(x-3\right)\left(x+3\right)}-\dfrac{2}{x-3}+\dfrac{1}{x+3}=0\\ \Leftrightarrow\dfrac{3x-1}{\left(x-3\right)\left(x+3\right)}-\dfrac{2\left(x+3\right)}{\left(x-3\right)\left(x+3\right)}+\dfrac{x-3}{\left(x+3\right)\left(x-3\right)}=0\\ \Rightarrow3x-1-2x-6+x-3=0\\ \Leftrightarrow2x-10=0\\ \Leftrightarrow2x=10\\ \Leftrightarrow x=5\)
\(o,\dfrac{1}{x+2}+\dfrac{2}{2-x}=\dfrac{2x-3}{x^2-4}\\ \left(\text{đ}k\text{x}\text{đ}:x\ne\pm2\right)\\ \Leftrightarrow\dfrac{1}{x+2}-\dfrac{2}{x-2}-\dfrac{2x-3}{\left(x-2\right)\left(x+2\right)}=0\\ \Leftrightarrow\dfrac{x-2}{\left(x+2\right)\left(x-2\right)}-\dfrac{2\left(x+2\right)}{\left(x-2\right)\left(x+2\right)}-\dfrac{2x-3}{\left(x-2\right)\left(x+2\right)}=0\\ \Rightarrow x-2-2x-4-2x-3=0\\ \Leftrightarrow-3x-9=0\\ \Leftrightarrow-3x=9\\ \Leftrightarrow x=-3\)
\(p,\dfrac{x+5}{x-5}-\dfrac{x-5}{x+5}=\dfrac{20}{x^2-25}\left(\text{đ}k\text{x}\text{đ}:x\ne\pm5\right)\\ \Leftrightarrow\dfrac{x+5}{x-5}-\dfrac{x-5}{x+5}-\dfrac{20}{\left(x-5\right)\left(x+5\right)}=0\\ \Leftrightarrow\dfrac{\left(x+5\right)^2}{\left(x-5\right)\left(x+5\right)}-\dfrac{\left(x-5\right)^2}{\left(x+5\right)\left(x-5\right)}-\dfrac{20}{\left(x-5\right)\left(x+5\right)}=0\\ \Rightarrow x^2+10x+25-x^2+10x-25-20=0\\ \Leftrightarrow20x-20=0\\ \Leftrightarrow20x=20\\ \Leftrightarrow x=1\)
`q,` giống `p,`
k: =>(x-2)(3x+5)-(2-x)(x+1)=0
=>(x-2)(3x+5)+(x-2)(x+1)=0
=>(x-2)(3x+5+x+1)=0
=>(x-2)(4x+6)=0
=>x=2 hoặc x=-3/2
l: (x+6)(5-x)=(x-5)(7x+8)
=>(x-5)(7x+8)=-(x-5)(x+6)
=>(x-5)(7x+8)+(x-5)(x+6)=0
=>(x-5)(7x+8+x+6)=0
=>(x-5)(8x+14)=0
=>x=-7/4 hoặc x=5
