`@` `\text {Ans}`
`\downarrow`
`a)`
\((x-1)^3=27\)
`=> (x-1)^3=3^3`
`=> x-1=3`
`=> x=3+1`
`=> x=4`
Vậy, `x=4`
`b)`
\((2x+1)^2=25\)
`=> (2x+1)^2=(+-5)^2`
`=>`\(\left[{}\begin{matrix}2x+1=5\\2x+1=-5\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}2x=4\\2x=-6\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=2\\x=-3\end{matrix}\right.\)
Vậy, `x \in {2; -3}`
`c)`
\(5^{x+2}=625\)
`=>`\(5^{x+2}=5^4\)
`=> x+2=4`
`=> x=4-2`
`=> x=2`
Vậy, `x=2.`
8:
a: =>x-1=3
=>x=4
b: =>2x+1=5 hoặc 2x+1=-5
=>x=2 hoặc x=-3
c: =>x+2=4
=>x=2