Question

Answer 1

\(\Leftrightarrow\left(x-2\right)-1+4x^2+2x+1-4x^2-4x=0\)

\(\Leftrightarrow-x=0\)

=>x=0

 

Answer 2

\(\Leftrightarrow x-2-1+\left(2x-1\right)\left(4x^2+4x+1\right):\left(2x-1\right)-4x^2-4x=0\)

\(\Leftrightarrow x-3+4x^2+4x+1-4x^2-4x\Leftrightarrow x-2=0\Leftrightarrow x=2\)

Answer 3

[(x - 2)³ - (2 - x)²] : (x - 2)² + (8x³ - 1) : (2x - 1) - 4x(x + 1) = 0

[(x - 2)³ + (x - 2)²] : (x - 2)² + [(2x - 1)(4x² + 2x + 1)] : (2x + 1) - 4x² - 4x = 0

x - 2 + 1 + 4x² + 2x + 1 - 4x² - 4x = 0

-x = 0

x = 0

Vậy x = 0