`a)2x(x-1)-3(x-1) =0`
`=> (2x-3)(x-1) =0`
`=> [ (2x-3=0),(x-1=0):}`
`<=>[(2x=3),(x=0+1):}`
`<=> [(x=3/2),(x=1):}`
Vậy `S={3/2;1}`
`b)x^2 -4x +4 =0`
`<=> x^2 - 2*x*2 +2^2 =0`
`<=> (x-2)^2 =0`
`=> x-2 =0 `
`<=> x = 2`
Vậy `S={2}`
`c)2x(5x+1)-10x-2=0`
`<=> 2x(5x+1) - 2(5x+1)=0`
`<=> (2x-2)(5x+1) =0`
`<=>[(2x-2=0),(5x+1=0):}`
`<=> [(2x=2),(5x=-1):}`
`<=> [(x=1),(x=-1/5):}`
Vậy `S={1;-1/5}`
`d)(x^2+4)(x-1) =0`
`<=>[ (x^2+4=0),(x-1=0):}`
`<=> (x^2 =-4(vô lí ) ), (x=1):}`
Vậy `S={1}`
`e)(x+2)(x+1)-x(x+2) =5`
`<=> x^2 +x+ 2x+2 - x^2 -2x =5`
`<=> x +2 =5`
`=> x =5-2 =3`
Vậy `S={3}`
một lần 2-3 câu thôi, những câu sau bạn đăng sau nha
\(a,\rightarrow\left(2x-3\right)\left(x-1\right)=0\\ \rightarrow2x-3=0hoặcx-1=0\\ \cdot2x-3=0\\ \rightarrow x=\dfrac{3}{2}\\ x\\ \cdot x-1=0\\ \rightarrow x=1\)
vậy \(x\in\left\{\dfrac{3}{2};1\right\}\)
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\(b,\rightarrow x^2-2x-2x+4=0\\ \rightarrow x\left(x-2\right)-2\left(x-2\right)=0\\ \rightarrow\left(x-2\right)\left(x-2\right)=0\\ \rightarrow\left(x-2\right)^0=0\\ \rightarrow x-2=0\\ \rightarrow x=2\)
