Bài 1:
a: \(x^2=16\)
=>x=4 hoặc x=-4
b: \(x^2=\left(-3\right)^2=9\)
=>x=3 hoặc x=-3
c: \(x^2=4-2\sqrt{3}\)
nên \(x^2=\left(\sqrt{3}-1\right)^2\)
=>\(\left[{}\begin{matrix}x=\sqrt{3}-1\\x=-\sqrt{3}+1\end{matrix}\right.\)
g: \(\left(x-2\right)^2=16\)
=>x-2=4 hoặc x-2=-4
=>x=6 hoặc x=-2
Bài 2
b) `sqrt{x} =3 `
`<=> `sqrt{x} = sqrt{9}`
`=> x=9`
b)`sqrt{x+1} = 1`
`<=> x + 1=1
`=> x = 0`
d)`sqrt{x-2} = 3`
`<=> x-2 = 9`
`<=> x = 9 + 2 =11`
e)`sqrt{4x+1} = 3`
`<=> 4x+1 = 9`
`=> 4x=9-1=8`
`<=> x = 8/4 =2`
f) `sqrt{x^2 +1} = sqrt{6}`
`<=> x^2 + 1=6`
`<=> x^2 = 6-1=5`
`<=>``x= +- sqrt{5}`
