Question

Answer 1

d: \(=2+\sqrt{3}-2+\sqrt{3}=2\sqrt{3}\)

Answer 2

\(c,=\dfrac{2-\sqrt{3}}{1}+\dfrac{\sqrt{3}}{3}-\dfrac{2\left(3-\sqrt{3}\right)}{6}\\ =2-\sqrt{3}+\dfrac{\sqrt{3}-3+\sqrt{3}}{3}=\dfrac{2\sqrt{3}-3+6-3\sqrt{3}}{3}=\dfrac{3-\sqrt{3}}{3}\\ d,=\sqrt{7+4\sqrt{3}}-\sqrt{7-4\sqrt{3}}=2+\sqrt{3}-2+\sqrt{3}=2\sqrt{3}\)