Question

Answer 1

\(a,x=9+4\sqrt{2}\Leftrightarrow\sqrt{x}=2\sqrt{2}+1\\ A=\dfrac{2\sqrt{2}+1+7}{2\sqrt{2}+1-1}=\dfrac{2\sqrt{2}+8}{2\sqrt{2}}\\ A=\dfrac{\sqrt{2}+4}{\sqrt{2}}=\dfrac{2+4\sqrt{2}}{2}=1+2\sqrt{2}\)

Answer 2

a: \(A=\dfrac{2\sqrt{2}+1+7}{2\sqrt{2}+1-1}=\dfrac{2\sqrt{2}+8}{2\sqrt{2}}=2\sqrt{2}+1\)