a, \(\frac{5}{x}+\frac{y}{4}=\frac{1}{8}\)
=> \(\frac{1}{8}-\frac{y}{4}=\frac{5}{x}\)
=>\(\frac{1}{8}-\frac{2y}{8}=\frac{5}{x}\)
=>\(\frac{1-2y}{8}=\frac{5}{x}\)
=>(1-2y).x = 8.5 = 40
Sau đó kẻ bảng
1-2y | 1 | 2 | 4 | 5 | 8 | 10 | 20 | 40 | |||
y | 0 | \(-\frac{1}{2}\) | \(-\frac{3}{2}\) | -2 | -3,5 | -4,5 | \(-\frac{19}{2}\) | \(-\frac{39}{2}\) | |||
x | 40 | 20 | 10 | 8 | 5 | 4 | 2 | 1 |
vậy ......................