Question

\(\left\{{}\begin{matrix}\frac{4}{x-2y}-\frac{1}{x-2y}=1\\\frac{20}{x+2y}+\frac{3}{x-2y}=1\end{matrix}\right.\)

giup mh vs

Answer 1

https://i.imgur.com/HFX5QWj.jpg

Answer 2

con cach nao khac ko vay

Answer 3

tai luc kt ket qua ko dung

Answer 4

Gọi \(\frac{1}{x-2y}=\)a ; \(\frac{1}{x+2y}=\)b

\(\left\{{}\begin{matrix}4a-a=1\\20b+3a=1\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}3a=1\\3a+20b=1\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}a=\frac{1}{3}\\b=0\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}\frac{1}{x-2y}=\frac{1}{3}\\\frac{1}{x+2y}=0\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}x-2y=3\\x+2y=0\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}2x=3\\x+2y=0\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}x=\frac{3}{2}\\y=-3\end{matrix}\right.\)

Answer 5

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