Question

tính giá trị biểu thức

\(\dfrac{6^2.6^3}{3^5}\)

\(\dfrac{25^2.4^2}{5^5.-2^5}\)

\(\dfrac{0,125^5.2,4^5}{-0,3^5.0,001^3}\)

\((2\dfrac{3}{4}+\dfrac{1}{2})\)

Answer 1

\(\dfrac{6^2.6^3}{3^5}=\dfrac{3^2.2^2.3^3.2^3}{3^5}=\dfrac{2^5.3^5}{3^5}=2^5=32.\)

\(\dfrac{25^2.4^2}{5^5.\left(-2\right)^5}=\dfrac{5^4.2^4}{\left(-10\right)^5}=\dfrac{10^4}{10^4.\left(-10\right)}=\dfrac{-1}{10}.\)

Answer 2

\(\dfrac{6^2.6^3}{3^5}=\dfrac{6^{2+3}}{3^5}=\dfrac{6^5}{3^5}=2^5=32\)

\(\dfrac{25^2.4^2}{5^5.\left(-2\right)^5}=\dfrac{\left(5^2\right)^2.\left(2^2\right)^2}{\left[5.\left(-2\right)\right]^5}=\dfrac{5^4.2^4}{-10^5}=\dfrac{10^4}{-10^5}=\dfrac{-1}{10}\)

\(\dfrac{0,125^5.2,4^5}{-0,3^5.0,001^3}=\dfrac{\left(0,125.2,4\right)^5}{-0,3^5.0,001^3}=\dfrac{0,3^5}{-0,3^5.0,001^3}=-\dfrac{1}{0,001^3}=-1000000000\)

\(\left(2\dfrac{3}{4}+\dfrac{1}{2}\right)=\dfrac{11}{4}+\dfrac{1}{2}=\dfrac{11}{4}+\dfrac{2}{4}=\dfrac{13}{4}\)

Answer 3

\(\dfrac{6^2.6^3}{3^5}=\dfrac{2^2.3^2.2^3.3^3}{3^5}=2^5=32\)

\(\dfrac{25^2.4^2}{5^5.-2^5}=\dfrac{5^4.2^4}{5^5.-2^5}=\dfrac{10^4}{-10^5}=\dfrac{1}{-10}=\dfrac{-1}{10}\)

\(\dfrac{0,125^5.2,4^5}{-0,3^5.0,001^3}=\dfrac{\left(\dfrac{1}{8}\right)^5.\left(\dfrac{12}{5}\right)^5}{-0,3^5.0,001^3}=\dfrac{0,3^5}{-0,3.0,001^5}\)

= \(\dfrac{1}{-0,001^5}\)

\(\left(2\dfrac{3}{4}+\dfrac{1}{2}\right)=\dfrac{11}{4}+\dfrac{1}{2}=\dfrac{11+2}{4}=\dfrac{13}{4}\)