\(0,2+\left|x-2,3\right|=1,1\)
\(\Rightarrow\left|x-2,3\right|=1,1-0,2=0,9\)
\(\Rightarrow\left[{}\begin{matrix}x-2,3=0,9\\x-2,3=-0,9\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=0,9+2,3=3,2\\x=-0,9+2,3=1,4\end{matrix}\right.\)
Vậy: x = 3,2 hoặc x = 1,4
\(0,2+\left|x-2,3\right|=1,1\)
=> \(\left|x-2,3\right|=1,1-0,2\)
=> \(\left|x-2,3\right|=0,9\)
=> \(\left[{}\begin{matrix}x-2,3=0,9\\x-2,3=-0,9\end{matrix}\right.=>\left[{}\begin{matrix}x=0,9+2,3\\x=-0,9+2,3\end{matrix}\right.=>\left[{}\begin{matrix}x=3,2\\x=1,4\end{matrix}\right.\)(T/M)