(x+5)2-(x+5)(x-5) = 20
⇔x2+10x+25-x2-25=20
⇔10x=20
⇔x=2
\(\left(x+5\right)^2-\left(x+5\right)\left(x-5\right)=20\)
\(\Leftrightarrow\)\(\left(x+5\right)\left[\left(x+5\right)-\left(x-5\right)\right]=20\)
\(\Leftrightarrow\left(x+5\right)\left[x+5-x+5\right]=20\)
\(\Leftrightarrow\left(x+5\right).10=20\)
\(\Leftrightarrow\)\(x+5=2\Rightarrow x=-3\)
(x+5)2-(x+5)(x-5) = 20
(x+5)2-(x+5)(x-5)-20=0
(x+5)-(x+5-x+5-20)=0
(x+5)-(2x-10)=0
x+5=0 hoặc 2x-10=0
x=-5 2x=10
x=5