\(\left(x^2-x+2\right)^2+\left(x-2\right)^2\)
\(=\left[\left(x^2-x+2\right)+\left(x-2\right)\right]^2-2.\left[\left(x^2-x+2\right).\left(x-2\right)\right]\)
\(=\left(x^2\right)^2-2.\left[\left(x^3-3x^2+4x-4\right)\right]\)
\(=x^4-2x^3+6x^2-8x+8.\)
\(=x^4-2x^3+2x^2+4x^2-8x+8\)
\(=\left(x^4-2x^3+2x^2\right)+\left(4x^2-8x+8\right)\)
\(=x^2.\left(x^2-2x+2\right)+4.\left(x^2-2x+2\right)\)
\(=\left(x^2-2x+2\right).\left(x^2+4\right)\)
Chúc bạn học tốt!
Tìm x biết : 6(x+2)(x-3)-3(x-2)^2-3(x-1)(x+1)=1
3(x+2)^2+(2x-1)^2-7(x+3)(x-3)=36
(x-1)(x^2+x+1)+x(x+2)(2-x)=5
(x-1)^3-(x+3)(x^2-3x+9)+3(x^2-4)=2
Tìm x biết : 6(x+2)(x-3)-3(x-2)^2-3(x-1)(x+1)=1
3(x+2)^2+(2x-1)^2-7(x+3)(x-3)=36
(x-1)(x^2+x+1)+x(x+2)(2-x)=5
(x-1)^3-(x+3)(x^2-3x+9)+3(x^2-4)=2
a) x+2/x-2-1/x=2/x*(x-2)
b)2/2x-6+2/2x+2+2x/(x+1)*(3-x)=0
c) x+1/2017+x+2/2016=x+3/2015+x+4/2014
d) x-45/5+x-44/6+x-43/7+x-42/8=4
e) x-3/2011+x+2/2012=x-2012/2+x-2011/3
\(\dfrac{2}{2^2-x^2}+\dfrac{1}{2x+x^2}\)
=\(\dfrac{2}{\left(2-x\right)\left(2+x\right)}+\dfrac{1}{x\left(x+2\right)}\)
=\(\dfrac{2x}{x\left(2-x\right)\left(2+x\right)}+\dfrac{\left(2-x\right)}{x\left(2-x\right)\left(2+x\right)}\)
=\(\dfrac{2x+2-x}{x\left(2-x\right)\left(2+x\right)}\)
=\(\dfrac{x+2}{x\left(2-x\right)\left(2+x\right)}\)
Giải phương trình:
1. (x - 5)2 + (x + 3)2 = 2(x - 4)(x + 4) - 5x + 7
2. (x + 3)(x - 2) - 2(x + 1)2 = (x - 3)2 - 2x2 + 4x
3. (x + 1)3 - (x + 2)(x - 4) = (x - 2)(x2 + 2x + 4) + 2x2
4. (x - 2)3 + (x - 5)(x + 5) = x(x2 - 5x) - 7x + 3
5. (x + 4)(x2 - 4x + 16) - x(x - 4)2 = 8(x - 3)(x + 3)
tìm x:
a) (x-5)(x+5)-(x-2)^2-7x^2+(x+1)(x^2-x+1)=(x+3)^3-(x^3+9x^2)
b) (2x+3)^2+(x-1)(x+1)=5(x+2)^2-(x-5)(x+1)+(x+4)^2
Tìm x biết:
1. (x-2)^2-(x-3)(x+3)=6
2. 4(x-3)^2-(2x-1)(2x+1)=10
3. (x-4)^2-(x-2)(x+2)=6
4.9(x+1)^2-(3x-2)(3x+2)=10
5. 3x +2(5-x)=0
6.x(2x-1)(x+5)-(2x^2+1)(x+4,5)=3,5
7, 3x^2-3x(x-2)=36
8. (3x^2-x+1)(x-1) +x^2(4-3x)=5/2
Giải phương trình :
8{x+1/x}^2+4{x^2+1/x^2}^2-4{x^2+1/x^2}{x+1/x}^2=(x+4)^2
a,(x+3)^2+(x-2).(x+2)-2(x-1)^2=7
b,(x+2)^2-(x-2)(x+2)=0
c,(3x-2)^2-(2x-1)^2=0
d,x^2-4x+3=0
\(\frac{2}{x+2}-\frac{2x^2+16}{x^3+8}=\frac{5}{x^2-2x+4}\)
\(\frac{2}{x^2-4}-\frac{x-1}{x\left(x-2\right)}+\frac{\left(x-4\right)}{x\left(x+2\right)}=0\)
\(\frac{1}{x-2}\frac{6}{x+3}=\frac{5}{6-x^2-x}\)
\(\frac{x+1}{x^2+x+1}-\frac{x-1}{x^2-x+1}=\frac{2\left(x+2\right)^2}{x^6-1}\)
