Question

\(\dfrac{2}{2^2-x^2}+\dfrac{1}{2x+x^2}\)

=\(\dfrac{2}{\left(2-x\right)\left(2+x\right)}+\dfrac{1}{x\left(x+2\right)}\)

=\(\dfrac{2x}{x\left(2-x\right)\left(2+x\right)}+\dfrac{\left(2-x\right)}{x\left(2-x\right)\left(2+x\right)}\)

=\(\dfrac{2x+2-x}{x\left(2-x\right)\left(2+x\right)}\)

=\(\dfrac{x+2}{x\left(2-x\right)\left(2+x\right)}\)

Answer 1

=\(\dfrac{1}{x\left(2-x\right)}\)(bổ sung thêm cho hoàn thiện)