Question

x mũ 2 (x-1)-16 (x-1)= 0 giúp vs ạ

 

Answer 1

\(x^2\left(x-1\right)-16\left(x-1\right)=0\\ \left(x^2-16\right)\left(x-1\right)=0\\ \left(x-4\right)\left(x+4\right)\left(x-1\right)=0\\ \Rightarrow\left[{}\begin{matrix}x-4=0\\x+4=0\\x-1=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=4\\x=-4\\x=1\end{matrix}\right.\)

Vậy..........

Answer 2

1+1 bằng mấy ạ

 

Answer 3

Ta có: \(x^2\left(x-1\right)-16\left(x-1\right)=0\)

\(\Leftrightarrow\left(x-1\right)\left(x-4\right)\left(x+4\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=1\\x=4\\x=-4\end{matrix}\right.\)