Question

(x-23).(x+ 6/7) = 0

Answer 1

(x-23).(x+ \(\dfrac{6}{7}\)) = 0

=> \(\left[{}\begin{matrix}x-23=0\\x+\dfrac{6}{7}=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=23\\x=\dfrac{-6}{7}\end{matrix}\right.\)

vậy x=23 hoặc x\(\dfrac{-6}{7}\)

Answer 2

Suy ra: (x-23)=0 hoặc (x+6/7)=0

TH1:x-23=0

x=0+23

x=23

TH2:x+6/7=0

x=0+6/7

x=6/7

Vậy x=23 hoặc x=6/7