Ta có : \(\left|x-1\right|-\left|x-3\right|=0\)
=> \(\left|x-1\right|=\left|x-3\right|\)
=> \(\left[{}\begin{matrix}x-1=x-3\\x-1=3-x\end{matrix}\right.\)
=> \(\left[{}\begin{matrix}3=1\left(L\right)\\2x=4\end{matrix}\right.\)
=> x = 2 .
Vậy ...
tìm x (x+1) (x+3) < 0
Tìm x,y biết :
1 ) | 4 - x | + | 2y +1 | = 0
2) | x - 3 | = | 5 - 2x |
tìm x biết :
\(\left|x-1\right|+2.\left|x-2\right|+3.\left|x-3\right|+4.\left|x-4\right|+5.\left|x-5\right|+20x=0\)
|x-3| + |y-2x | =0
|x| + 3|2x -x ² | =0
|5x ² -5 | + 4|y-7 | =0
||x +1 | + |y-5 |=0
|x ² -1| + |y-1| =0
|x-1 | +|x ²-x |=0
Tìm x biết:
a) x^2-3.x=0
b) 2.x^2+5.x=0
c) x^2+1=0
d) x^2-1=0
e) x.(x-3)-x+3=0
g) x^2.(x+2)-9.x-18=0
Tìm x:
A, (x-3)(x-2)<0
B, (2x-1)(x-2)<0
C, (x+3)(x-4)>0
D, x^2(x+1)> hoặc bằng 0
E, (3x+1)(x-2)(x^2+1)>0
Tìm x biết:
A, (x+3)(x-2)<0
B, (2x-1)(x-2)<0
C, (x+3)(x-4)>0
D, x^2 (x+1)> hoặc = 0
E, (3x+1)(x-2)(x^2+1)>0
Bài 1 : Tìm x
a) 2/3 - 1/3 (x-3/2)-1/2(2x+1)=5
b) (x+1/2)(X-3/4)=0
c) 1/3 x + 3/5 (x+1)=0
d)x-8/2 > 0
e) x:(2/9 - 1/5 )=1/2
g) 1/3 + 1/2 : x = 1/5
Bài 1 : Tìm x
a) 2/3 - 1/3 (x-3/2)-1/2(2x+1)=5
b) (x+1/2)(X-3/4)=0
c) 1/3 x + 3/5 (x+1)=0
d)x-8/2 > 0
e) x:(2/9 - 1/5 )=1/2
g) 1/3 + 1/2 : x = 1/5
Tìm x,y,z biết: \(\left|x-\frac{1}{2}\right|+\left|y+\frac{2}{3}\right|+\left|x^2+xz\right|=0\)
