\(2x\left(x+3\right)-x\left(5+2x\right)=27\)
\(\Leftrightarrow2x^2+6x-5x-2x^2=27\)
\(\Leftrightarrow6x-5x-27=0\)
\(\Leftrightarrow x=27\)
\(S=\left\{27\right\}\)
Tìm x bt
1) 3.(2x−1).(3x−1)−(2x−3).(9x−1)−3=−3
2) 3x−1.(2x+7)−x+1.(6x−5)=x+2−(x−5)
3) 3xy.(x+y)−(x+y).(x2+y2+2xy)+y3=27
4) 5.x+1.(1−x).(2x2+3)=0
giúp mk vs mai mk đi hk rù
Tìm x bt
1) 3.(2x−1).(3x−1)−(2x−3).(9x−1)−3=−3−3
2) 3x−1.(2x+7)−x+1.(6x−5)=x+2−(x−5)
3) 3xy.(x+y)−(x+y).(x2+y2+2xy)+y3=27
4) 5.x+1.(1−x).(2x2+3)=0
giúp mk vs mai mk đi hk rùi
B1: Tính nhân 1.(2×x-1)(3x^2 -x+1) 2.(2x^2 -3xy+y^2)(x+y) 3.(x^2-1)(x^2+2x) 4.(x+3)(x^2+3x-5)
Bài1:Làm tính nhân:
a) 2x. (x2– 7x -3) b) ( -2x3+ y2-7xy). 4xy2 c)(-5x3).(2x2+3x-5)
d)(x2-2x+3). (x-4) e) ( 2x3-3x -1). (5x+2) g) 3(2x-1)-5(x-3)
rút gọn
(2x-1)(3-2x)+(2x+3)^2
(2x-1)^2 - x(4x-2)
(x+4)(x-3)-(x-5)^2
(2-3x)(x+4)+(2x-5)^2
(x-1)(2x+3)-(x+2)^2
BT: Tìm x
a) 2x.(x-3)-x(2x+1)-3.(x+5)=11
b) x.(x-1)-(x^2+3x-5)-2.(x+3)=7
c) 5x.(x-7)-(5x+1).x-(x+3).2=13
d) (2x^2-3x+5)-2x.(x-3)+(x-1).(-2)=10
tìm x.
a, 2x(x-5)-x(3+2x)=26
b, x(2x2-3)-2x2(5-2x)+8x2-4x3=7
Tìm x :
a/2x(x - 1) - x(4 - x) = 0
b/3(1 - 4x)(x - 1) + 4(3x - 2)(x + 3)=-27
Tìm x biết:
a) \(\left(3x-1\right)\left(2x+7\right)-\left(x+1\right)\left(6x+5\right)=x+2-\left(x-5\right)\)
b) \(\left(x+1\right)\left(x+2\right)\left(x+5\right)-x^3-8x^2=27\)
