\(3\left(x-3\right)\left(x+7\right)+\left(x-4\right)^2+48\)
\(=3\left(x^2+7x-3x-21\right)+x^2-8x+16+48\)
\(=3x^2+12x-63+x^2-8x+64\)
\(=4x^2+4x+1=4x^2+2x+2x+1\)
\(=2x\left(2x+1\right)+\left(2x+1\right)=\left(2x+1\right)^2\)(1)
Thay \(x=0,5\) vào (1) ta có:
\(\left(2.0,5+1\right)^2=\left(1+1\right)^2=2^2=4\)
Vậy..................
Chúc bạn học tốt!!!