b, B=202-192+182-172+...+22-12
=(202-192)+(182-172)+...+(22-12)
= (20-19)(20+19)+(18-17)(18+17)+..+(2-1)(2+1)
=39+35+...+3
=\(\xrightarrow[10sốhạng]{3+..+35+39}\)
=\(\frac{\left(39+3\right).10}{2}=210\)
Vậy B =210
a) \(A=85^2+2\cdot85\cdot15+15^2\)
\(A=\left(85+15\right)^2=100^2=10000\)
b) \(B=\left(20-19\right)\left(20+19\right)+\left(18-17\right)\left(18+17\right)+...+\left(2+1\right)\left(2-1\right)\)\(B=39+35+...+3\)
\(=\frac{\left(39+3\right)\left[\left(39-3\right):4+1\right]}{2}\)
\(=\frac{42\cdot10}{2}=210\)