\(\left(3^2\right)^2-\left[\left(-5\right)^2\right]^2+\left[\left(-2\right)^3\right]^2\\ =3^4-\left(-5\right)^4+\left(-2\right)^6\\ =81-625+64\\ =\left(81+64\right)-625\\ =145-625=-480\)
\(\left(3^2\right)^2-\left[\left(-5\right)^2\right]^2+\left[\left(-2\right)^3\right]^2\\ =3^4-\left(-5\right)^4+\left(-2\right)^6\\ =81-625+64\\ =\left(81+64\right)-625\\ =145-625=-480\)
\(\left\{\left[\left(2\sqrt{2}\right)^2:2,4\right]X\left[5,25:\left(\sqrt{7}\right)^2\right]\right\}\) : \(\left\{\left[2\dfrac{1}{7}:\dfrac{\left(\sqrt{5}\right)^2}{7}\right]:\left[2^2:\dfrac{\left(2\sqrt{2}\right)^2}{\sqrt{81}}\right]\right\}\)
b, tìm x, y, z thoả mãn đẳng thức
\(\sqrt{\left(x-\sqrt{2}\right)^2}\) + \(\sqrt{\left(y+\sqrt{2}\right)^2}\) + |x + y + z| = 0
tính
a) \(\left[\dfrac{0.8\div\left(\dfrac{4}{5}\cdot1025\right)}{0.64-1}+\dfrac{\left(1.08-\dfrac{2}{25}\right)\div\dfrac{4}{7}}{\left(6\dfrac{5}{7}-3\dfrac{1}{4}\right)\cdot2\dfrac{2}{17}}+\left(1.2\cdot0.5\right)\div\dfrac{4}{5}\right]\)
b) \(\left(0.2\right)^{-3}\left[\left(-\dfrac{1}{5}\right)^{-2}\right]^{-1}+\left[\left(\dfrac{1}{2}\right)^{-3}\right]^{-2}\div\left(2^{-3}\right)^{-1}-\left(0.175\right)^{-2}\)
c) \(2+\dfrac{1}{1+\dfrac{1}{2+\dfrac{1}{1+\dfrac{1}{2}}}}\)
d) \(\dfrac{1}{90}-\dfrac{1}{72}-\dfrac{1}{56}-\dfrac{1}{42}-\dfrac{1}{3}\)
e) \(\left(\dfrac{1}{3}\right)^{-1}-\left(-\dfrac{6}{7}\right)^0+\left(\dfrac{1}{2}\right)^2\div2\)
f) \(\dfrac{\dfrac{1}{3}-\dfrac{1}{7}-\dfrac{1}{13}}{\dfrac{2}{3}-\dfrac{2}{7}-\dfrac{2}{13}}\cdot\dfrac{\dfrac{3}{4}-\dfrac{3}{16}-\dfrac{3}{64}-\dfrac{3}{256}}{1-\dfrac{1}{4}-\dfrac{1}{16}-\dfrac{1}{64}}+\dfrac{5}{8}\)
g) \(\dfrac{1}{-\left(2017\right)\left(-2015\right)}+\dfrac{1}{\left(-2015\right)\left(-2013\right)}+...+\dfrac{1}{\left(-3\right)\cdot\left(-1\right)}\)
h) \(\left(1-\dfrac{1}{1\cdot2}\right)+\left(1-\dfrac{1}{2\cdot3}+...+\left(1-\dfrac{1}{2017\cdot2018}\right)\right)\)
Tìm x,biết
a, \(\frac{3}{\left(x+2\right)\left(x+5\right)}+\frac{5}{\left(x+5\right)\left(x+10\right)}+\frac{7}{\left(x+10\right)\left(x+17\right)}=\frac{x}{\left(x+2\right)\left(x+17\right)}\)
Với x ∉ -2,-5,-10,-17
b,\(\frac{2}{\left(x-1\right)\left(x-3\right)}+\frac{5}{\left(x-3\right)\left(x-8\right)}+\frac{12}{\left(x-8\right)\left(x-20\right)}-\frac{1}{x-20}=\frac{-3}{4}\)
Với x∉1,3,8,20
c,\(\frac{x-1}{2009}+\frac{x-2}{2008}=\frac{x-3}{2007}+\frac{x-4}{2006}\)
\(\left(\dfrac{1}{2}\right)^3.\left[\left(\dfrac{1}{2}\right)^X\right]^X-\dfrac{5}{8}=\left(\dfrac{1}{2}\right)^4.\left(-9\right)\)
\(\dfrac{\left(\dfrac{-1}{2}\right)^3-\left(\dfrac{3}{4}\right)^3.\left(-2\right)^2}{2.\left(-1\right)^5+\left(\dfrac{3}{4}\right)^2-\dfrac{3}{8}}\)
Rút gọn biểu thức trên
1) \(\left|3x+2\right|=\left|x+1\right|\)
2) \(\left|\left(x+2\right)\times x\right|=\left|x+2\right|\)
3) \(\left|2x+3\right|=x+1\)
4) \(\left|4x+5\right|+3.x=7\)
tìm x biết:
a) \(\left(x-2\right)^2+\left(y-3\right)^2=0\)
b) \(5^{\left(x-2\right).\left(x+3\right)}=1\)
c) \(-\left(-x-y\right)^2=\left(yz-3\right)^2\)
\(5^{\left(x-2\right).\left(x+3\right)}=1\)
\(-\left(x-y\right)^2=\left(y-3\right)^2\)
\(7^{\left(2x-1\right).\left(3x-1\right)}=1\)
tính giá trị của mỗi biểu thức A,B,C,D rồi sắp xếp các kết quả tìm được theo thứ tự tăng dần:
A=\(\dfrac{5}{4}.\left(5-\dfrac{4}{3}\right).\left(-\dfrac{1}{11}\right)\) B=\(\dfrac{3}{4}:\left(-12\right).\left(-\dfrac{2}{3}\right)\)
C=\(\dfrac{5}{4}:\left(-15\right).\left(-\dfrac{2}{5}\right)\) D=\(\left(3\right).\left(\dfrac{2}{3}-\dfrac{5}{4}\right):\left(-7\right)\)