Question

Tính giá trị biểu thức

\(T=(2\sqrt{3}+1)(3\sqrt{2}-1)\sqrt{13-4\sqrt{3}}.\sqrt{19+6\sqrt{2}}\)

Answer 1

\(T=\left(2\sqrt{3}+1\right)\left(3\sqrt{2}-1\right)\sqrt{13-4\sqrt{3}}.\sqrt{19+6\sqrt{6}}\)

\(T=\left(2\sqrt{3}+1\right)\left(3\sqrt{2}-1\right)\sqrt{\left(2\sqrt{3}-1\right)^2}.\sqrt{\left(3\sqrt{2}+1\right)^2}\)

\(T=\left(2\sqrt{3}+1\right)\left(3\sqrt{2}-1\right)\left|2\sqrt{3}-1\right|.\left|3\sqrt{2}+1\right|\)

\(T=\left(2\sqrt{3}+1\right)\left(3\sqrt{2}-1\right)\left(2\sqrt{3}-1\right)\left(3\sqrt{2}+1\right)\)

\(T=\left(2\sqrt{3}+1\right)\left(2\sqrt{3}-1\right)\left(3\sqrt{2}-1\right)\left(3\sqrt{2}+1\right)\)

\(T=11\cdot17\)

\(T=187\)

Answer 2

hay Băng nào em :v? Mình là Huyền :))

Answer 3

Phạm Thị Diệu Huyền lúc thì trai lúc thì gái ai biết bà :v