ĐKXĐ: \(x\ge1;y\ge4\)
\(x-1-2\sqrt{x-1}+1+y-4-4\sqrt{y-4}+4=0\)
\(\Leftrightarrow\left(\sqrt{x-1}-1\right)^2+\left(\sqrt{y-4}-2\right)^2=0\)
\(\Leftrightarrow\left\{{}\begin{matrix}\sqrt{x-1}-1=0\\\sqrt{y-4}-2=0\end{matrix}\right.\) \(\Leftrightarrow\left\{{}\begin{matrix}\sqrt{x-1}=1\\\sqrt{y-4}=2\end{matrix}\right.\) \(\Leftrightarrow\left\{{}\begin{matrix}x=2\\y=8\end{matrix}\right.\)