Question

tìm xy nguyên biết

xy-3x-2y=5

Answer 1

Ta có: xy-3x-2y=5

\(\Leftrightarrow\) x(y-3)-2y+6=5+6

\(\Leftrightarrow\) x(y-3)-(2y-6)=11

\(\Leftrightarrow\) x(y-3)-2(y-3)=11

\(\Leftrightarrow\) (x-2)(y-3)=11=1.11=11.1=(-1).(-11)=(-11).(-1)

\(\Rightarrow\left[{}\begin{matrix}x-2=1;y-3=11\\x-2=11;y-3=1\\x-2=\left(-1\right);y-3=\left(-11\right)\\x-2=\left(-11\right);y-3=\left(-1\right)\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=3;y=14\\x=13;y=4\\x=1;y=\left(-8\right)\\x=\left(-9\right);y=2\end{matrix}\right.\)

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