a) xy+3x-y-5=0
(xy+3x)-y-3-2=0
x(y+3)-(y+3)-2=0
(x-1)(y+3)=0+2=2
Ta có: 2=1.2=2.1=(-1).(-2)=(-2).(-1)
\(\Rightarrow\left[{}\begin{matrix}x-1=1;y+3=2\\x-1=2;y+3=1\\x-1=\left(-1\right);y+3=\left(-2\right)\\x-1=\left(-2\right);y+3=\left(-1\right)\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=2;y=\left(-1\right)\\x=3;y=\left(-2\right)\\x=0;y=\left(-5\right)\\x=\left(-1\right);y=\left(-4\right)\end{matrix}\right.\)
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