x; y thuộc Z ; \(\sqrt{y}+\sqrt{x}=\sqrt{2017}\)
\(x,y\in N;x,y\le2017\)
\(\Leftrightarrow y=2017+x-\sqrt{2017x}\)
\(x;y\in N\Rightarrow\sqrt{2017x}\in N;2017la.so.n.to\Rightarrow x=2017\)
\(\left(x;y\right)=\left(0;2017\right);\left(2017;0\right)\)