|2x-1| = |2x+3|
=>2x-1=-(2x+3) hoặc 2x+3
Xét 2x-1=-2x-3
=>4x=-2
=>\(x=-\frac{1}{2}\)
Xét 2x-1=2x+3
=>2x-1-2x-3=0
=>-4=0 (loại)
Vậy \(x=-\frac{1}{2}\)
\(\left|2x-1\right|=\left|2x+3\right|\\ =>2x-1=-2x+3ho\text{ặ}c2x+3\\ \)
TH1:\(2x-1=-2x+3\\ =>2x-1=-\left(2x+3\right)\\ =>4x=-2\\ =>x=-\frac{1}{2}\)
TH2:\(2x-1=2x+3\\ =>2x-1-2x-3=0\\ =>-4=0\left(lo\text{ại}\right)\)
Vậy \(x=-\frac{1}{2}\)