Question

Tìm x , y , z biết :

\(x=\dfrac{y}{2}=\dfrac{z}{3}và4x-3y+2z=16\)

Answer 1

Từ x = \(\dfrac{y}{2}=\dfrac{z}{3}\)

=> \(\dfrac{4x}{4}=\dfrac{3y}{6}=\dfrac{2z}{6}\)

Áp dụng t/c dãy tỉ số bằng nhau:

\(\dfrac{4x}{4}=\dfrac{3y}{6}=\dfrac{2z}{6}=\dfrac{4x-3y+2z}{4-6+6}=\dfrac{16}{4}=4\)

Từ \(\dfrac{4x}{4}=4\), => x = \(\dfrac{4.4}{4}\)= 4

Từ \(\dfrac{3y}{6}=4\), => y = \(\dfrac{4.6}{3}\) = 8

Từ \(\dfrac{2z}{6}=4\), => z = \(\dfrac{4.6}{2}\) = 12

Vậy ..