\(\left|5x-3\right|-x=7\)
TH1: \(5x-3\ge0\rightarrow x\ge\frac{3}{5}\)
\(\rightarrow5x-3-x=7\)
\(\rightarrow4x=10\)
\(\Rightarrow x=\frac{5}{2}\)
TH2: \(5x-3< 0\rightarrow x< \frac{3}{5}\)
\(\rightarrow-5x+3-x=7\)
\(\rightarrow-6x=4\)
\(\Rightarrow x=-\frac{2}{3}\)
Vậy \(x\in\left\{\frac{5}{2};-\frac{2}{3}\right\}\)
Nhớ tik
\(\left|5x-3\right|-x=7\)
Ta có 2 trường hợp
TH1: \(5x-3\ge0\Rightarrow5x\ge3\Rightarrow x\ge\frac{3}{5}.\)
\(\Rightarrow5x-3-x=7\)
\(\Rightarrow5x-x=7+3\)
\(\Rightarrow4x=10\)
\(\Rightarrow x=10:4\)
\(\Rightarrow x=\frac{5}{2}.\)
TH2: \(5x-3< 0\Rightarrow5x< 3\Rightarrow x< \frac{3}{5}.\)
\(\Rightarrow-5x+3-x=7\)
\(\Rightarrow-5x-x=7-3\)
\(\Rightarrow-6x=4\)
\(\Rightarrow x=4:\left(-6\right)\)
\(\Rightarrow x=-\frac{2}{3}.\)
Vậy \(x\in\left\{\frac{5}{2};-\frac{2}{3}\right\}.\)
Chúc bạn học tốt!
