Question

tìm x

\(\left(x-2013\right)^{2014}=1\)

Answer 1

\(\left(x-2013\right)^{2014}=1\\ \Leftrightarrow x-2013\in\left\{-1;1\right\}\\ \Leftrightarrow x\in\left\{2012;2014\right\}\)

Vậy....

Answer 2

(x−2013)2014=1

=> (x-2013)²⁰¹⁴=1²⁰¹⁴

=> x-2013=1

=> x=2014

Answer 3

ta có : \(\left(x-2013\right)^{2014}=1\Leftrightarrow\left[{}\begin{matrix}x-2013=\sqrt[2014]{1}\\x-2013=-\sqrt[2014]{1}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x-2013=1\\x-2013=-1\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=2014\\x=2012\end{matrix}\right.\) vậy \(x=2014;x=2012\)

Answer 4

\(\left(x-2013\right)^{2014}=1\)

\(\Leftrightarrow\left(x-2013\right)^{2014}=\left(\pm1\right)^{2014}\)

\(\Leftrightarrow\left[{}\begin{matrix}x-2013=1\\x-2013=-1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2014\\x=2012\end{matrix}\right.\)

Answer 5

(x-2013)²⁰¹⁴=1

(x-2013)²⁰¹⁴=1²⁰¹⁴

x-2013=1

Suy ra x=1+2013

x=2014

Answer 6

ta có\(\left(x-2013\right)^{2014}=1\)

\(\Rightarrow x-2013=1\)

\(\Rightarrow x=2014\)

Answer 7

TH2

\(x-2013=-1\)

\(\Rightarrow\)x=2012

Answer 8

(x - 2013)²⁰¹⁴ =1

=> (x-2013)²⁰¹⁴ = 1²⁰¹⁴

=> x-2013 = 1

=> x= 1+2013

=> x=2014