Question

tim x

\(\frac{1}{2}\cdot\left(x-3\right)-\frac{1}{3}=\frac{1}{6}\)

Answer 1

\(\frac{1}{2}\left(x+3\right)=\frac{1}{3}+\frac{1}{6}=\frac{1}{2}\)

⇔x-3=1

⇔x=4

Answer 2

Tìm x :

\(\frac{1}{2}.\left(x-3\right)-\frac{1}{3}=\frac{1}{6}\)

⇒ \(\frac{1}{2}.\left(x-3\right)=\frac{1}{6}+\frac{1}{3}\)

⇒ \(\frac{1}{2}.\left(x-3\right)=\frac{1}{6}+\frac{2}{6}\)

⇒ \(\frac{1}{2}.\left(x-3\right)=\frac{3}{6}\)

⇒ \(x-3=\frac{3}{6}:\frac{1}{2}\)

⇒ \(x-3=\frac{3}{6}.\frac{2}{1}\)

⇒ \(x-3=\frac{6}{6}\)

\(\Rightarrow x-3=1\)

⇒ \(x=1+3\)

⇒ \(x=4\)

Vậy : \(x=4\)

Answer 3

\(\frac{1}{2}.\left(x-3\right)-\frac{1}{3}=\frac{1}{6}\)

\(\Rightarrow\frac{1}{2}.\left(x-3\right)=\frac{1}{6}+\frac{1}{3}\)

\(\Rightarrow\frac{1}{2}.\left(x-3\right)=\frac{1}{2}\)

\(\Rightarrow\left(x-3\right)=\frac{1}{2}:\frac{1}{2}\)

\(\Rightarrow x-3=1\)

\(\Rightarrow x=1+3\)

\(\Rightarrow x=4\)

Vậy \(x=4.\)

Chúc bạn học tốt!