Question

Tìm x

\(\dfrac{x-2}{3}-x+3=\dfrac{x+2}{2}-\dfrac{x+2}{6}\)

Answer 1

\(\dfrac{x-2}{3}-x+3=\dfrac{x+2}{2}-\dfrac{x+2}{6}\)

\(\dfrac{x}{3}-\dfrac{2}{3}-x+3=\dfrac{x}{2}+\dfrac{2}{2}-\dfrac{x}{6}-\dfrac{2}{6}\)

\(\dfrac{x}{3}-\dfrac{2}{3}-x+3=\dfrac{x}{2}+1-\dfrac{x}{6}-\dfrac{1}{3}\)

\(\dfrac{x}{3}-x+\left(3-\dfrac{2}{3}\right)=\dfrac{x}{2}-\dfrac{x}{6}+1-\dfrac{1}{3}\)

\(\dfrac{-2}{3}x+\dfrac{7}{3}=\dfrac{1}{3}x+\dfrac{2}{3}\)

\(\dfrac{7}{3}-\dfrac{2}{3}=\dfrac{1}{3}x+\dfrac{2}{3}x\)

\(\dfrac{5}{3}=\dfrac{3}{3}x\)

\(\Rightarrow\dfrac{5}{3}=x\)

Vậy x cần tìm là \(\dfrac{5}{3}\)