( 12x-5)( 4x-1)+ ( 3x-7)(1-16x)
=> 48x^2-48x^2-12x-20x+3x+112x+5-7=81
=> 83x-2=81
=> x=1
(12x - 5)(4x - 1) + (3x - 7)(1 - 16x) = 81
48x2 - 12x - 20x + 5 + 3x - 48x2 - 7 + 112x = 81
83x - 2 = 81
83x = 81 + 2
83x = 83
x = 1
( 12x-5)( 4x-1)+ ( 3x-7)(1-16x)
=> 48x^2-48x^2-12x-20x+3x+112x+5-7=81
=> 83x-2=81
=> x=1
(12x - 5)(4x - 1) + (3x - 7)(1 - 16x) = 81
48x2 - 12x - 20x + 5 + 3x - 48x2 - 7 + 112x = 81
83x - 2 = 81
83x = 81 + 2
83x = 83
x = 1
B1 ( kết quả thôi ko cần lời giải)
a) \(\left(4x-3\right)\left(3x+2\right)-\left(6x+1\right)\left(2x-5\right)+1\)
b) \(\left(3x+4\right)^2+\left(4x-1\right)^2+\left(2+5x\right)\left(2-5x\right)\)
c) \(\left(2x+1\right)\left(4x^2-2x+1\right)+\left(2-3x\right)\left(4+6x+9x^2\right)-9\)
B2 tìm x(kết quả)
a) \(3x\left(x-4\right)-x\left(5+3x\right)=-34\)
b) \(\left(3x+1\right)^2+\left(5x-2\right)^2=34\left(x+2\right)\left(x-2\right)\)
c) \(x^3+3x^2+3x+28=0\)
8. Làm tính nhân :
a) \(\left(x^2y^2-\frac{1}{2}xy+2y\right)\left(x-2y\right)\)
b) (x2-xy+y2)(x+y)
13. Tìm x, biết :
(12x-5)(4x-1)+(3x-7)(1-16x)=81
14.
Tìm 3 số tự nhiên chẵn liên tiếp, biết tích của 2 số sau lớn hơn tích của 2 số đầu là 192.
Giải các PT sau:
a)\(2x\left(8x-1\right)^2\left(4x-1\right)=9\)
b)\(\left(12x+7\right)^2\left(3x+2\right)\left(2x+1\right)=3\)
c)\(\left(2x+1\right)\left(x+1\right)^2\left(2x+3\right)=18\)
Tìm x
\(\left(x-3\right)^3-x.\left(3x+1\right)^2+\left(2x+1\right).\left(4x^2-2x+1-3x^2\right)\)
Tim x
a) \(\left(x+3\right)^3-x.\left(3x+1\right)^2+\left(2x+1\right).\left(4x^2-2x+1-3x^2\right)=54\)
b) \(\left(x-3\right)^3-\left(x-3\right).\left(x^2+3x+9\right)+6.\left(x+1\right)^2+3x^2=-33\)
cho \(Q\left(x\right)=x^4+mx^3+nx^2+px+q\) biết \(Q\left(1\right)=5,Q\left(2\right)=7,Q\left(3\right)=9,Q\left(4\right)=11\).
Tìm m,n,p,q và tính \(Q\left(10\right),Q\left(11\right),Q\left(12\right),Q\left(13\right)\)
HELP ME.... mình cảm ơn
tìm x biết :
\(\frac{1}{\left(x-1\right)x}+\frac{1}{\left(x-2\right)\left(x-1\right)}+\frac{1}{\left(x-3\right)\left(x-2\right)}+\frac{1}{\left(x-4\right)\left(x-3\right)}=\frac{x}{x^2-4x}\)
Tim x
a) \(\left(4x+3\right).\left(4x-3\right)-\left(4x-5\right)^2=46\)
b) \(\left(x+1\right)^3+2x-\left(x-1\right)^3-3.\left[\left(x+1\right)^2+\left(x-1\right)^2\right]+5=0\)
1)\(\frac{8xy\left(3x-1\right)^3}{12x^3\left(1-3x\right)}\)
2)\(\frac{5x^3+5x}{x^4-1}\)
3)\(\frac{9-\left(x+5\right)^2}{x^2+4x+4}\)
4)\(\frac{32x-8x^2+2x^3}{x^3+64}\)